10p^2-3=-12p

Solution for 10p^2-3=-12p equation:

10p^2-3=-12p

We move all terms to the left:

10p^2-3-(-12p)=0

We get rid of parentheses

10p^2+12p-3=0

a = 10; b = 12; c = -3;
Δ = b2-4ac
Δ = 122-4·10·(-3)
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{66}}{2*10}=\frac{-12-2\sqrt{66}}{20}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{66}}{2*10}=\frac{-12+2\sqrt{66}}{20}
$